Question

The area of a triangular park is 4800 sq m. The length of its base is 80 m ,
find its height.

Answer 1

Answer:

120m²

Step-by-step explanation:

Area of triangle ABC= 1/2×B×H

4800m² = 1/2× 80×H

4800m²= 40×H

4800/40=H

120m²=H

Height= 120m²

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Answer 2

❍ Let the base and height of the triangle be b and h respectively.

• It is given that area of the triangular park is 4800m² and length of thebase of the triangular park is 80m.

_________________________

For finding the area of the triangle, formula is given as :

$\: \:$

$\underline{\boxed{\sf{Area_{(triangle)} = \frac{1}{2} \times b \times h}}}$

$\: \:$

$\sf:\implies \: Area_{(triangle)} = \dfrac{1}{2} \times b \times h \\ \\ \\ \sf:\implies \: 4800 = \frac{1}{2} \times 80 \times h \\ \\ \\ \sf:\implies \: h = \frac{4800 \times 2}{80} \\ \\ \\ \sf:\implies \: h = \cancel\frac{9600}{80} \\ \\ \\ \sf:\implies \:\underline{\boxed{\sf{}h = 120m}} \\ \\ \\ \\ \sf\therefore{\underline{Hence, \: the \: height \: of \: the \:triangular \: park \: is \: \bold{120m}. }}$