Question

The area of AABC is 71 sq. units. A is at (-19, y), B is at (-5, -16), and C is at (-11,-5). Also, y is an integer. Find y.​

Answer 1

Answer:

Step-by-step explanation:

let, A = $\left[\begin{array}{ccc}-19&y&1\\-5&-16&1\\-11&-5&1\end{array}\right]$

Area of the triangle = (1/2)det(A)

and given that,

(1/2)det(A) = 71

or,(-19)(-16+5)-y(-5+11)+1(25-176) = 142

or, 304 - 95 -6y -151 = 142

or , -6y = 388 - 304

or, y = -84/6

or, y = - 14