The area of ∆ ABC, if perimeter of the triangle is 42m.and two sides of the ∆ are equal and the unequal side is 12 m. , is
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=71.28sq units
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Answer:
Area of the ∆ is 18√21 m²
Step-by-step explanation:
Perimeter = 42m
Opposite sides are equal,
Third side is 12m
So, 2x+12=42 [let equal sides be x]
or, 2x=42-12
or, x=30/2
or, x=15
Semiperimeter = 42/2m =21m
Using Herons Formula,
Area of the ∆,
=√(21(21-15)(21-15)(21-12))
=√(21×6×6×9)
=√(7×3×3×2×3×2×3×3)
=3×3×2√(7×3)
=18√21 m²
Therefore area of the ∆ is 18√21m².
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