The area of an ellipse is twice that of a circle. The major diameter of the ellipse is twice that of the minor diameter.
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....and the question is????
Maybe you need to express the major and minor diameters of the ellipse in terms of the radius of the circle?
Let a be half the major diameter. Let b be half the minor diameter. Let r be the radius of the circle.
Given: a = 2b
area of ellipse = 2 × area of circle
=> π a b = 2 × π r²
=> a b = 2 r²
=> ( 2b ) b = 2 r²
=> b² = r²
=> b = r ( both are positive values )
=> a = 2b = 2r.
So the minor diameter is the same as the diameter of the circle.
The circle sits inside the ellipse, tangent to it on two sides.
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