The area of an equilateral triangle inscribed in the circle x^2+y^2=a2
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Answer:x2 + y2 - 6x + 2y - 15 = 0
Centre O = (3, -1)
radius r = √{32 + (-1)2 -(-15)} = √{9 + 1 + 15 } = √25 = 5
Also ∠OBD = 60
From right angle triangle OBD,
sin 60 = BD/OB
=> √3/2 = BD/r
=> BD = r*√3/2
Also, BC = 2*BD = 2*r*√3/2 = √3r
Now, area of the triangle ABC = √3/4 * a2 {a is the side of the triangle ABC}
Step-by-step explanation:
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