The area of an equilateral triangle is 49√3. Taking Each angular point as centre, circles are drawn with radius equal to half the length of the side of the triangle. Find the area of the triangle not included in the circles.(Use √3=1.73)
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Area of equilateral ∆ = √3/4 × (side)^2
49√3 = √3/4 (side)^2
(Side)^2 = 49×4
Side = 7×2
[Side = 14cm]
Area of sector = 60°/360° × π×(7)^2
= 1/6 × 22/7 ×49
= 77/3
Area not covered = Area(∆ABC) -3×Area(sector)
=49√3 - 77/3 ×3
=49√3 - 77
=84.77 - 77
= 7.77 cm^2
So 7.77 cm^2 area is not included!
49√3 = √3/4 (side)^2
(Side)^2 = 49×4
Side = 7×2
[Side = 14cm]
Area of sector = 60°/360° × π×(7)^2
= 1/6 × 22/7 ×49
= 77/3
Area not covered = Area(∆ABC) -3×Area(sector)
=49√3 - 77/3 ×3
=49√3 - 77
=84.77 - 77
= 7.77 cm^2
So 7.77 cm^2 area is not included!
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