Question

the area of an equilateral triangle is 49√3cm^2 . find its height

Answer 1

let the ABC be the required triangle where AB =BC=CA = a cm
let the AD be the height(h)
now, BD = CD = a/2 cm
now 49√3 = √3 a^2/ 4
from the above equation a = 14 cm
Also, 1/2 × a × h = 49√3
now, a = 14 cm
hence your answer is 7√3 cm