the area of an equilateral triangle is 49 root 3 cm square taking each angular. As Centre circle is drawn with radius equal to the half of the length of the side of a triangle find the area of triangle not equal included in the circles
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Let "a" be the side of equilateral triangle.
3√a24=493√;a2=49*4;a= 7*2=14 cm;
Radius of circle = 14/2 = 7 cm
Area of the first circle occupied by triangle = area of sector
=12r2θ=12*72*π*60180=773cm2
Area of all the 3 sectors = 77/3 * 3 = 77 cm2
Area of triangle not included in the circle
= area of triangle- area of all the 3 sectors
==493√−77=7.87cm2
3√a24=493√;a2=49*4;a= 7*2=14 cm;
Radius of circle = 14/2 = 7 cm
Area of the first circle occupied by triangle = area of sector
=12r2θ=12*72*π*60180=773cm2
Area of all the 3 sectors = 77/3 * 3 = 77 cm2
Area of triangle not included in the circle
= area of triangle- area of all the 3 sectors
==493√−77=7.87cm2
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