The area of an expanding rectangle is increase at the rate of 48 cm. The length of the rectangle is equal to the square of the breadth . At what rate is the length increasing at the instant when the breadth is 4.5 cm
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Let the area at time t be A=A (t), and let the breadth at time t be x=x(t). Then the length at time t is x^2, and therefore
A=x^3.
Differentiate with respect to t, using the Chain Rule. We get
dA/dt = 3x^2dx/dt…………………………………………………………(1)
Now freeze the situation at the instant that x=4.5.
We know dA/dt, and we know x, so from (1) we can find dx/dt at that time.
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