The area of an isoceles triangle with a non equal side 4cm and one equal side 8cm is
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this is the process of getting the value..where we need to put the value of a ,b,and c then find the answer...which is 60
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a=8cm b=8cm c=4cm
perimeter of isoceles∆=a+b+c\2
8+8+4\2
2o÷2=10
area of isoceles∆=√s(s-a)(s-b)(s-c)
√10(10-8)(10-8)(10-4)
√2*5*2*2*2*3
4*15=60
perimeter of isoceles∆=a+b+c\2
8+8+4\2
2o÷2=10
area of isoceles∆=√s(s-a)(s-b)(s-c)
√10(10-8)(10-8)(10-4)
√2*5*2*2*2*3
4*15=60
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