Math, asked by jhamalti666, 1 year ago

The area of an isosceles ∆is 8√15 cm ^2 if the base is 8cm find the length of each of its equal sides

Answers

Answered by naavyya
36

Answer:

2√19 cm

Step-by-step explanation:

Area of the triangle = 8√15 cm² ; base = 8cm

Area of the triangle = 1/2 * base * height

8√15 = 1/2 * 8 * height

8√15 = 4 * height

Height = 8√15 / 4

Height = 2√15  cm

In triangle ABC, AB =AC ;  AD = DC = 8/2 = 4cm

Triangle ADC is a right angled triangle.

Using Pythagoras Theorem,

AC² = AD² + DC²

AC² = (2√15)² + 4²

AC² = (4 * 15) + 16

AC² = 60 + 16

AC² = 76

AC² = 4 * 19

AC = √4 * √19

AC = 2√19 cm

∴The length of equal sides is 2√19 cm

Attachments:
Answered by furrygaming14
18

Answer:

2√19 cm

Step-by-step explanation:

Step-by-step explanation:

Area of the triangle = 8√15 cm² ; base = 8cm

Area of the triangle = 1/2 * base * height

8√15 = 1/2 * 8 * height

8√15 = 4 * height

Height = 8√15 / 4

Height = 2√15  cm

In triangle ABC, AB =AC ;  AD = DC = 8/2 = 4cm

Triangle ADC is a right angled triangle.

Using Pythagoras Theorem,

AC² = AD² + DC²

AC² = (2√15)² + 4²

AC² = (4 * 15) + 16

AC² = 60 + 16

AC² = 76

AC² = 4 * 19

AC = √4 * √19

AC = 2√19 cm

∴The length of equal sides is 2√19 cm

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