Question

The area of an isosceles right angle traingle is 200 sq .m. find its hypotenuse​

Answer 1

Answer:

The hypotenuse is 20√2 cm.

Step-by-step explanation:

hope it is helpful

Answer 2

Answer:

20√2 cm

Step-by-step explanation:

Let the equal sides of isosceles triangle be x cm

$AB=BC=x$

We know,

$\longmapsto \underline{\boxed{\bold{Area\:of\:triangle = \frac{1}{2} \times BC\times AB}}}$

$\Rightarrow 200 = \frac{1}{2} \times x \times x$

$\Rightarrow x^2 = 400$

$\Rightarrow x = 20cm$

$AB=BC = 20$

By using pythagoras theorem

$\longmapsto \underline{\boxed{\bold{AC^2=AB^2+BC^2}}}$

$\Rightarrow AC^2= 20^2+20^2$

$\Rightarrow AC^2 = 400+400$

$\Rightarrow AC^2 = 800$

$\Rightarrow AC = \sqrt{800}$

$\Rightarrow AC =\sqrt{400\times2}$

$\Rightarrow AC =\sqrt[20]{2}$

∴ The hypotenuse= $\sqrt[20]{2}$