The area of an isosceles right-angle triangle is 50 cm”, find out the perimeter of the triangle?
1. 10(2 + 2 ) cm 2. 12(2 + 12 ) cm 3.11(3 + 12 ) cm 4.13(4 + 2)cm
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Answered by
0
Answer:
a+b+5=12
a+b=7⇒a=7−b...(1)
a2+b2=52
a2+b2=25...(2)
From (1) and (2)
(7−b)2+b2=25
49+b2−14b+b2=25
2b2−14b+24=0
b2−7b+12=0
(b−4)(b−3)=0
⇒b=4,3
a=7−b⇒a=3,4
Area=21×4×3=6sq. units
Answered by
4
Answer:
a+b+5=12 (1)
a+b=7
a=7-b
a2+b2=52
a2+b2=25(2)
From 1 and 2
(7-b)2+b2=25
49+b2-14b+b2=25
2b2-14b+24=0
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