the area of an isosceles right angled triangle is 128 cmsq. find its perimeter.
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area of a triangle = 1/2 bh
In a right angled isosceles triangle the base and height are the same.
so, let height and base be = a
area of the triangle = 1/2 x a x a = 128cmsq.
1/2 x a² = 128
a² = 128 x 2 = 256
a = √256 = 16
perimeter of a triangle = a + a + hypotenuse
a² + a² = hypotenuse²
16² + 16² hypotenuse ²
512 = hypotenuse²
hypotenuse = √512 = 22.6
perimeter = 16+16+22.6 = 54.6 approx.
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