Question

The area of an isosceles triangle each of whose equal sides is 13m and whose base is 24m

Answer 1

Answer:

212.3 sq.m

Step-by-step explanation:

Answer 2

Answer:

60 $m^{2}$

Step-by-step explanation:

base/4$\sqrt{4*(equal side^{2})-base^{2}$

24/4$\sqrt {4(13^{2})-24^{2}$

6$\sqrt{4(169)-576$

6$\sqrt{676-576$

6$\sqrt{100$

6*10

60$m^{2}$