Question

The area of an isosceles triangle each of whose equal sides is 13 m and whose base is 24 m =​

Answer 1

Answer:

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Step-by-step explanation:

Let AABC is an isosceles triangle.

In which,

ABAC = 13 cm

And,

BC= 24 cm

Therefore,

Area of triangle ABC = 1/4 xB under root4A2-B²

=> 1/4 x 24 x under root 4 × (13)² - (24)²

=>[1/2 x 24 x under root 4 × 169 - 24 x 24] cm²

=> [1/4 × ( 676 - 576)]

=> 6 x rot 100

=> 6 × 10

=> 60 cm²