The area of an isosceles triangle each of whose equal sides is 13cm and whose base is 24 cm is.
Answers
Answered by
1
Answer:base * height /2
13*24/2
hence 13*12
is 156 cm²
Step-by-step explanation:
hope it helps you mark as brainliest
Answered by
2
Answer:
Given,
Length of the equal sides = 13cm
Base = 24 cm
To find = Area of the triangle.
Now,
Area of an isosceles triangle:
= ¼ b√4a²-b²
= ¼× 24√4(13)²-24²
= 6√4x169-576
=6√676-576
= 6√100
= 6x10
= 60 cm²
Thus, the area of the triangle is 60 cm².
Similar questions