Math, asked by anonymousbeing0123, 1 month ago

The area of an isosceles triangle each of whose equal sides is 13cm and whose base is 24 cm is. ​

Answers

Answered by subashr33
1

Answer:base * height /2

13*24/2

hence 13*12

is 156 cm²

Step-by-step explanation:

hope it helps you mark as brainliest

Answered by punyanyasha246
2

Answer:

Given,

Length of the equal sides = 13cm

Base = 24 cm

To find = Area of the triangle.

Now,

Area of an isosceles triangle:

= ¼ b√4a²-b²

= ¼× 24√4(13)²-24²

= 6√4x169-576

=6√676-576

= 6√100

= 6x10

= 60 cm²

Thus, the area of the triangle is 60 cm².

Similar questions