Math, asked by spideygaming180, 3 months ago

The area of an isosceles triangle having 12cm as its unequal side and 32 as its perimeter will be

Answers

Answered by Anonymous
0

Step-by-step explanation:

Now area of any triangle is 1/2 of base× height. The height of the triangle has a line from centre of base to the meeting point of equal sides.

Answered by panashyadav
0

let the two sides be x.

12 cm + x + x = 32 cm

12 cm + 2x = 32 cm

2x = ( 32 - 12 )cm

2x = 20 cm

x = 20 / 2 cm

x = 10 cm

so the two sides be 10 cm.

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