The area of an isosceles triangle having 12cm as its unequal side and 32 as its perimeter will be
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Step-by-step explanation:
Now area of any triangle is 1/2 of base× height. The height of the triangle has a line from centre of base to the meeting point of equal sides.
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let the two sides be x.
12 cm + x + x = 32 cm
12 cm + 2x = 32 cm
2x = ( 32 - 12 )cm
2x = 20 cm
x = 20 / 2 cm
x = 10 cm
so the two sides be 10 cm.
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