Question

The Area of an isosceles triangle having a base of 2cm and the length of the equal sides 4cm is

Answer 1

Answer:

The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is. √15 cm.

Answer 2

As per the data given in the question,

We have to determine the value of area of isosceles triangle.

From the data it is given that,

Base of triangle = 2 cm

Length of two equal sides = 4 cm.

So, we will use Heron's Formula for determining the value of area.

So, applying Heron's Formula,

We know that,

$Area={\sqrt{s(s-a)(s-b)(s-c)}}$

Where, s = semi-circumference of triangle.

$s=\frac{a+b+c}{2} = \frac{2+4+4}{2}=\frac{10}{2} = 5\:cm$

So, applying the formula,

$Area={\sqrt{s(s-a)(s-b)(s-c)}}\\Area={\sqrt{5(5-2)(5-4)(5-4)}}\\Area={\sqrt{5\times 3\times 1\times 1)}}\\Area = {\sqrt{15}} \:Sq.\:cm$

Hence, area of isosceles triangle will be ${\sqrt{15}}\:Sq.\:cm$