the area of an isosceles triangle having Base 2 cm and length of of one of the equal sides 4cm
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Answered by
3
the answer is 4cm
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Answered by
25
Answer:
Step-by-step explanation:
Let the sides of the triangle be a,b,c
then a=2cm ,b=4cm ,c=4cm
s=(a+b+c)/2
=(2+4+4)/2
=10/2
=5cm
now we can find area by heron's formula
So, Area=(s*(s-a)(s-b)(s-c))root 1/2
=(5*3*1*1)root1/2
=root 15cm^2
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