Question

The area of an isosceles triangle having base1 2 cm and the length of one of the equal sides 7 cm, is​

Answer 1

Given :

• Base of an isosceles triangle is 12 cm
• The length of one of the equal sides is 7 cm.

To find :

• The area of an isosceles triangle =??

Solution :

Let ,

• a = 2 cm
• b = 4 cm
• c = 4 cm

Using Heron's formula as:

${\underline { \boxed { \bf { \red{A=\sqrt{s(s-a)(s-b)(s-c)}}}}}} \: \green \bigstar$

s is semi perimeter,

$: \implies \tt \: s=\dfrac{a+b+c}{2}$

$: \implies \tt \: s=\dfrac{2+4+4}{2}$

$: \implies \tt \: s=5 \: cm$

Now using the above formula as :

$:\implies\tt \: A=\sqrt{5\times (5-2)(5-4)(5-4)}$

$: \implies \tt \: A=\sqrt{5\times 3\times 1\times 1}$

$: \implies\tt \: A=\sqrt{15} \ cm^2$

So, the area of an isosceles triangle is $\bf\sqrt{15} \ cm^2$.

Answer 2

Answer:

√15cm ²

Step-by-step explanation:

Hope it helps Maria's BRAINLIEST