The area of an isosceles triangle is 12 cm^2 and the base is 8 cm in length. Find the perimeter of the triangle.
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this is the answer I think so
the perimeter is 16 cm
the perimeter is 16 cm
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Given, Area of isosceles triangle = 12 cm^2 and base = 8 cm.
We know that Area = (1/2) * base * height
⇒ 12 = (1/2) * 8 * h
⇒ 12 = 4h
⇒ h = 3 cm.
Now,
By Pythagoras theorem,
We know that c^2 = (b/2)^2 + h^2
⇒ c^2 = (8/2)^2 + 3^2
⇒ c^2 = 4^2 + 9
⇒ c^2 = 16 + 9
⇒ c^2 = 25
⇒ c = 5 cm.
Now, Perimeter of triangle:
⇒ (2 * 5) + 8
⇒ 18 cm.
Therefore, perimeter of triangle = 18 cm.
Hope it helps!
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