Question

The area of an isosceles triangle is 5/

4√

11 cm^2

. If its base is 5 cm, then length of equal side is​

Answer 1

Answer:

True Justification: According to the question,

Perimeter = 11 cm And

base, a = 5

As the triangle is isosceles, b = c

Perimeter = 11 ⇒ a + b + c = 11 ⇒

5 + b + b = 11 ⇒ 5 + 2b = 11

⇒ 2b = 6 ⇒ b = 3

So, we have, a = 5, b = 3, c = 3 s

= (a + b + c)/2 ⇒ s = (5 + 3 + 3)/2 = 11/2

Area of triangle = √s(s-a)(s-b)(s-c) ⇒ Area of triangle = (5√11)/4 cm2

Hence, the statement “The area of the isosceles triangle is 5/4√11 cm2, if the perimeter is 11 cm and the base is 5 cm” is True.

Step-by-step explanation: