Question

The area of an isosceles triangle is 60 cm and the length of one of its equal sides is 13 cm. Find the length of the third side. AN The harta analen​

Answer 1

Answer:

hb≈9.23cm

Step-by-step explanation:

Answer 2

Answer:

third side = base

area =

$\frac{1}{2} \times b \times \frac{}{?} \sqrt{ {a}^{2} - \frac{b}{4} } \\ {a}^{2} = 13 \times 13 =169 \\ let \: b \: be \: x \\ \frac{1}{2} \times x\times \sqrt{169 - \frac{x}{4} } = 60 \\ \frac{1}{2} \times x \times \sqrt{169 - x} = 60 \times 4 \\ = \frac{1}{2} \times \sqrt{169 - x } = \frac{240}{x} = \\ \frac{1}{2} \times 13 - \sqrt{x} = 240 \div x \\ \frac{1}{2} \times 13 = 240 \div x + {x}^{2} \\ \frac{13}{2} = \frac{240}{x} + {x}^{2} \\ 480 + {x}^{2} = 13x \\ x = \frac{480 - {x}^{2} }{13} \\ \\ {2x}^{2} = \frac{480}{13} \\ {x}^{2} = \frac{480 \div 13}{2} \\ x = \sqrt{240 \div 13} \\ x = 4.29$

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