Math, asked by nilupatel2912, 5 months ago

the area of an isosceles triangle whose bar is 2cm and one of the equal side
 \sqrt{ \frac{15}{2} }  {cm}^{2}

Answers

Answered by Anonymous
1

s=  

2

4+4+2

​  

=5

Area of the triangle

Δ=  

s(s−a)(s−b)(s−c)

​  

 

=  

5(5−4)(5−4)(5−2)

​  

=  

15

​  

cm  

2

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