Question

the area of an isosceles triangle whose base is 4cm and one of the equal sides is 8cm is ​

Answer 1

Answer:

we know that ,

* height of two sides of isosceles triangle is equal ,Then side of the isosceles triangle is 8and8 cm

* base of isosceles triangle is 4cm

* area of isosceles triangle. = 1/2×b×h

= 1/2×4×8

= 4×4

= 16

Answer 2

draw a straight line from vertex to opposite side

by using Pythagoras theorem

8²=2²+x²

64=4+x²

x²=64-4

x²=60

x=√60

x=2√15

area of triangle is 1/2 bh

1/2(4)(2√15)

=4√15

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