Question

the area of an isosceles triangle whose base is a and equal sides are of length b is

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Answer 1

Answer:

Given base = a, and length of equal side = b

Using Pythagoras theorem, we can find the height of the triangle (shown in the attachment below).

Now we have height = √(b²-(a/2)²)

So area of the triangle = Half * base * height

=>   $\frac{1}{2} * a * \sqrt{(b^{2}-(\frac{a}{2} )^{2}) }$