Question

the area of an isosceles triangle whose equal sides are equal to 4 cm and the other side is 6 CM its area is​

Answer 1

Answer:

wlcm

So here ,

The sides triangle of is

A=4

B= 4

as we know two sides of isosceles triangle is equal

and third side

C=6

So here,

Semi perimeter is

S=a+b+c/2

=4+4+6/2

=14/2

=7

So here we using Heron's formula, we get,

=√s(s-a)(s-b)(s-c)

=√7(7-4)(7-4)(7-6)

=√7×3×3×1

=3√7×1

=3√7 ans

So here

The area of isosceles triangle whose equal sides are equal to 4 cm and the other side is 6cm and its area is3√7

Thnk u

Answer 2

by pylhagoras theorem.

$3 { }^{2} + \times { }^{2} = 4 {}^{2}$

$x {}^{2} = 4 {}^{2} - 3 {}^{2}$

$x {}^{2} = 16 - 9$

$x { }^{2} = 7$

$x = \sqrt{7}$

1/2×b×h = 1/2×6×√7=3√7