Question

the area of arhombus is 240 CM square and one of the diagonals is 16 find the other diagonal ​

Answer 1

Answer:

30cm.

Step-by-step explanation:

The area of the given rhombus is 240cm. A rhombus has two diagonal, which connect the opposite vertices, and the parallel sides. Thus using congruent triangles it can be said that a rhombus is symmetry along the diagonals.

Therefore, the “area of the rhombus” is equal to

since area of rhombus= 1/2×d1+d2

240=1/2×16×d2

240=8×d2

240÷8=d2

d2=30cm

Now the “area of the rhombus” is given as  which if equated gives  

Therefore, one of the diagonals of the rhombus of area 240, is 16 and the other one is 30cm.

Answer 2

Answer:

D² = 30cm

Step-by-step explanation:

d¹=diagonal 1

d²=diagonal 2

Let the length of one diagonal d¹=16cm

And the length of the other diagonal =d²

$Area \: of \: the \: rhombus = \frac{1}{2} \: d {}^{1}.d {}^{2} = 240</p><p>$

$So, \: \frac{1}{2} = 16..d {}^{2} = 240$

$Therefore, \: d {}^{2} = 30cm$

$Hence \: the \: length \: of \: the \: second \: \\ diagonal \: is \: 30cm \: or \: d {}^{2} = 30cm$