Physics, asked by Anonymous, 7 months ago

The area of base of a cylindrical vessel is 200 cm 2 . Water (density = 1000 kg m -3 ) is poured into it up to a depth of 8 cm. Calculate (a) the pressure and (b) the thrust of water on the base. (g = 10 ms -2 )

Answers

Answered by Aayush0803
0

Answer:

Pressure =f/a

Pressure =8/200m2

0.04

Hope you understood

Thankyou

Answered by Anonymous
7

 \bold{(a) \: The  \: pressure} \\  \bold{Height \:  = \:  6cm  \: to  \: m} \\  \bold{ =  \:  \frac{6}{100} } \\  \bold{ =  \: 0.06 \: m} \\  \bold{Density  \: =  \: 1000 \:  kgm^-3} \\ \bold{Acceleration \:  due \:  to  \: gravity  \: =  \: 10ms^-2} \\  \bold \green{pressure \:  =  \: hpg}  \\  \bold{ =  \: 0.06 \: m \times 1000 \: kgm^-3 \times 10 \: ms^-2} \\  \bold \red{ =  \: 600 \: Pa \:  \: ....ans}

 \bold{(b) \: The  \: thrust  \: of \:  water  \: on  \: the \:  base} \\  \bold{Pressure \:  =  \:  \frac{force}{area} } \\  \bold \green{force \:  =  \: Pressure \times area} \\  \bold{ =  \: 600 \: Pa \times 300 \:  {cm}^{2} } \\  \bold \red{ =  \: 18 \: N \:  \: ....ans}

hope it helps you....

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