Question

The area of base of a
cylindrical vessel is 200 cm
square.Water is poured into it up
to a depth of 5cm. Find i)
pressure ii) The thrust of water on
the base( g=10m/s^2). Take
density of water 1000kg/m^3​

Answer 1

Answer:

pressure is 50000 pa. and thrust is 1000 Newton...pls mark me brainliest

Explanation:

as we know that:p=hdg

5*1000*10=50kilo. Pascal,,

and p=f/areabso,,

50000=f/0.02mthrust=50000*0.02==1000N answer

Answer 2

$\bold{(a) \: The \: pressure} \\ \bold{Height \: = \: 6cm \: to \: m} \\ \bold{ = \: \frac{6}{100} } \\ \bold{ = \: 0.06 \: m} \\ \bold{Density \: = \: 1000 \: kgm^-3} \\ \bold{Acceleration \: due \: to \: gravity \: = \: 10ms^-2} \\ \bold \green{pressure \: = \: hpg} \\ \bold{ = \: 0.06 \: m \times 1000 \: kgm^-3 \times 10 \: ms^-2} \\ \bold \red{ = \: 600 \: Pa \: \: ....ans}$

$\bold{(b) \: The \: thrust \: of \: water \: on \: the \: base} \\ \bold{Pressure \: = \: \frac{force}{area} } \\ \bold \green{force \: = \: Pressure \times area} \\ \bold{ = \: 600 \: Pa \times 300 \: {cm}^{2} } \\ \bold \red{ = \: 18 \: N \: \: ....ans}$

hope it helps you....

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