Question

The area of base of a cylindrical vessel is 300 cm^2. Water
(density = 1000 kg m^-3) is poured into it up to a depth
of 6 cm. Calculate : (a) the pressure and (b) the thrust
of water on the base. (8 = 10 m s^-2).​

Answer 1

$\huge \mathcal {\fcolorbox{red}{gray}{\green{A}\pink{N}\orange{S}\purple{W}\red{E}\blue{R}}}$

$area = 300 {cm}^{2} \\ = \frac{300}{10000} = 0.03 {m}^{2} \\ density = 1000 {kg}^{3}per \: {m}^{3} \\ height \: or \: depth = 6cm = 0.06m$

$1)pressure = ? \\ p = hdg \\ = 0.06 \times 1000 \times 10 \\ { \large{ \red{ \underline{ \ = 600 \: pascal}}}}$

$2) \: { \large{ \bold{ \ thrust = ?}}} \\ thrust = \: pressure \times area \\ = 600 \times 0.03 \\{ \large{ \bold{ \underline{ \red{ \ = 18 \: newton}}}}}$

${\huge\mathcal{\fcolorbox{lime}{black}{\pink{FROM☞ ADESH \: KUMAR}}}}$