Question

The area of base of a cylindrical vessel is 300 cm?. Water (density = 1000 kg * m ^ - 3) is poured into it up to a depth of 6 cm. Calculate : (a) the pressure and (b) the thrust of water on the base. (g = 10m * s ^ - 2) . PLZ TELL THE ANSWER​

Answer 1

Answer

Given Area of base of vessel , a = 300 cm2 = 300 × 10-4 m2

Density of water , ρ = 1000 kg m-3

Depth , h = 6 cm = 0.06 m

Acceleration due to gravity , g = 10 ms-2

(a) Pressure = hρg = 0.06 × 1000 × 10 = 600 pascal

(b) Thrust , T = pressure × area = 600 × 300 × 10-4 = 18 N

Explanation:

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