Question

the area of base of a right circular cylender is 412 cm*and height is 12cm What is its volume?​

Answer 1

Answer:

• Volume of a cylinder is 1704 cm³.

Step-by-step explanation:

Given that:

• The area of base of a right circular cylinder is 412 cm².
• Height of a cylinder is 12 cm.

To Find:

• What is its volume?

Formula used:

• Volume of a cylinder = Area of base × Height

Finding the volume of cylinder:

• Volume = (142 cm² × 12 cm)
• Volume = 1704 cm³

More formula of right circular cylinder:

1. Total surface area = 2πr(r + h)
2. Curved surface area = 2πrh
3. Area of base = πr²

Here,

• r = Radius of base of a cylinder
• h = Height of a cylinder

Answer 2

Answer:

$\Large \underline \red{\sf \pmb{Given}}$

• ➠ The area of base of a right circular cylender is 412 cm²
• ➠ Height of cylinder is 12cm.

$\rule{200}2$

$\Large\underline \red{\sf \pmb{To \: Find}}$

• ➠ Volume of cylinder

$\rule{200}2$

$\Large \underline \red{\sf \pmb{Using \: Formula }}$

${\underline {\boxed{ \sf{Volume \: of \: cylinder =Area \: of \: Base × Height }}}}$

$\rule{200}2$

$\Large \underline \red{\sf \pmb{Solution}}$

${\implies\sf{Volume \: of \: cylinder =Area \: of \: Base × Height }}$

${\implies\sf{Volume \: of \: cylinder =142 \: {cm}^{2} × 12 \:cm }}$

${\implies\sf{Volume \: of \: cylinder =1704 \: {cm}^{3} }}$

$\Large\underline \red{\sf \pmb{Therefore}}$

• ➠ The Volume of cylinder is 1704 cm³

$\rule{200}2$

$\Large \underline \red{\sf \pmb{Additional \: Information }}$

$\begin{gathered}\begin{gathered}\bigstar \: \bf\underline{More \: Useful \: Formulae } \: \bigstar  \\ \begin{gathered}{\boxed{\begin{array} {cccc}{\sf{{\leadsto TSA \: of \: cube \: = \: 6(side)^{2}}}} \\  \\{\sf{{\leadsto LSA \: of \: cube \:= \: 4(side)^{2}}}}  \\  \\{\sf{{\leadsto Volume \: of \: cube \: = \: (side)^{3}}}} \\  \\ {\sf{{\leadsto Diagonal \: of \: cube \: = \: \sqrt(l^{2} + b^{2} + h^{2}}}} \\  \\ {\sf{{\leadsto Perimeter \: of \: cube \: = \: 4(l+b+h)}}} \\  \\ {\sf{{\leadsto CSA \: of \: sphere \: = \: 2 \pi r^{2}}}} \\  \\ {\sf{{\leadsto SA \: of \: sphere \: = \: 4 \pi r^{2}}}} \\  \\{\sf{{\leadsto TSA \: of \: sphere \: = \: 3 \pi r^{2}}}} \\  \\ {\sf{{\leadsto Diameter \: of \: circle \: = \: 2r}}} \\  \\ {\sf{{\leadsto Radius \: of \: circle \: = \: \dfrac{d}{2}}}} \\  \\ {\sf{{\leadsto Volume \: of \: sphere \: = \: \dfrac{4}{3} \pi r^{3}}}} \\  \\ {\sf{{\leadsto Area \: of \: rectangle \: = \: Length \times Breadth}}} \\  \\ {\sf{{\leadsto Perimeter \: of \: rectangle \: = \:2(length+breadth)}}} \\  \\{\sf{{\leadsto Perimeter \: of \: square \: = \: 4 \times sides}}}\end{array}}}\end{gathered}\end{gathered}\end{gathered}$