The area of circle is given by the expression piex^2+6piex+9pie. Find the radius of the circle
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given area=πX^2+6πX+9π. Let R is radius of this circle then Area=πR^2
πX^2+6π+9π=πR^2 so here π is common and so it get cancelled and R^2=X^2+6X+9
R^2=(X+3)^2.... R=X+3
πX^2+6π+9π=πR^2 so here π is common and so it get cancelled and R^2=X^2+6X+9
R^2=(X+3)^2.... R=X+3
sangeetaag24:
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pi x^2 + 6pi x + 9 pi = pi ( x^2 + 6x + 9 )
= pi ( x + 3 )^2
=> r = ( x + 3 )
= pi ( x + 3 )^2
=> r = ( x + 3 )
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