Question

The area of contact of the brick with powdered lime when it is placed vertically is 0.02 m2 calculate the pressure exerted by the brick of weight 30 N on the lime powder

Answer 1

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⋆ This question says that we have to find out the pressure that is exerted by the brick that have a weight of 30 Newton's on the lime power where the area of contact of the brick with powdered lime when it is placed vertically is 0.02 metres sq. Let's solve this question!

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$\sf According \: to \: statement \begin{cases} & \sf{Weight \: = \bf{30 \: Newton}} \\ \\ & \sf{Area \: of \: contact \: of \: brick \dots \: = \bf{0.02 \: m^{2}}} \\ \\ & \sf{Pressure \: = \bf{?}} \end{cases}$

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➟ The force acting on an object perpendicular to the surface is known as thrust.

➟ The thrust on unit area is known as pressure. Henceforth,

${\small{\underline{\boxed{\sf{Pressure \: = \dfrac{Thrust}{Area}}}}}}$

It can be also written as

${\small{\underline{\boxed{\sf{Pressure \: = \dfrac{Force}{Area}}}}}}$

➟ SI unit of pressure is N/m² but in honour of scientist Blaise Pascal it's SI is Pascal that is denoted by Pa.

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~ Using the formula to find pressure let's find the pressure exerted by the brick on the lime powder. Let's do it!

$:\implies \sf Pressure \: = \dfrac{Force}{Area} \\ \\ :\implies \sf Pressure \: = \dfrac{30}{0.02} \\ \\ :\implies \sf Pressure \: = \cancel{\dfrac{30}{0.02}} \qquad (Cancelling) \\ \\ :\implies \sf Pressure \: = \cancel{\dfrac{15}{0.01}} \qquad (Cancelling) \\ \\ :\implies \sf Pressure \: = \dfrac{15 \times 100}{1} \\ \\ :\implies \sf Pressure \: = \dfrac{1500}{1} \\ \\ :\implies \sf Pressure \: = 1500 \: Pascal$

Solution: 1500 Pa is the force exerted by the brick on the lime powder.