Question

The area of contact of the brick with powdered lime when it is placed vertically is 0.02m^2 calculate the pressure exerted by the brick of weight 30 N on the lime powder. plz amswer my question ​

Answer 1

${\bigstar \:{\pmb{\sf{\underline{Understanding \:the \:question...}}}}}$

⋆ This question says that we have to find out the pressure that is exerted by the brick that have a weight of 30 Newton's on the lime power where the area of contact of the brick with powdered lime when it is placed vertically is 0.02 metres sq.

${\bigstar \:{\pmb{\sf{\underline{Provided \: that...}}}}}$

$\sf According \: to \: statement \begin{cases} & \sf{Weight \: = \bf{30 \: Newton}} \\ \\ & \sf{Area \: of \: contact \: of \: brick \dots \: = \bf{0.02 \: m^{2}}} \\ \\ & \sf{Pressure \: = \bf{?}} \end{cases}$

${\bigstar \:{\pmb{\sf{\underline{Knowledge \: required...}}}}}$

➟ The force acting on an object perpendicular to the surface is known as thrust.

➟ The thrust on unit area is known as pressure. Henceforth,

${\small{\underline{\boxed{\sf{Pressure \: = \dfrac{Thrust}{Area}}}}}}$

It can be also written as

${\small{\underline{\boxed{\sf{Pressure \: = \dfrac{Force}{Area}}}}}}$

➟ SI unit of pressure is N/m² but in honour of scientist Blaise Pascal it's SI is Pascal that is denoted by Pa.

${\bigstar \:{\pmb{\sf{\underline{Full \: Solution...}}}}}$

~ Using the formula to find pressure let's find the pressure exerted by the brick on the lime powder. Let's do it!

$:\implies \sf Pressure \: = \dfrac{Force}{Area} \\ \\ :\implies \sf Pressure \: = \dfrac{30}{0.02} \\ \\ :\implies \sf Pressure \: = \cancel{\dfrac{30}{0.02}} \qquad (Cancelling) \\ \\ :\implies \sf Pressure \: = \cancel{\dfrac{15}{0.01}} \qquad (Cancelling) \\ \\ :\implies \sf Pressure \: = \dfrac{15 \times 100}{1} \\ \\ :\implies \sf Pressure \: = \dfrac{1500}{1} \\ \\ :\implies \sf Pressure \: = 1500 \: Pascal$

Solution: 1500 Pa is the force exerted by the brick on the lime powder.