The area of cross-section of a hosepipe is 8 cm². Water is pumped into an empty
cuboidal swimming pool through this pipe at a speed of 40 kmph. If the length and
the breadth of the pool are 50 m and 8 m respectively find the depth of water in it after
30 minutes.
Answers
Answered by
0
Step-by-step explanation:
Volume flow rate=av=
t
V
∴ v
1
=
A
1
t
V
=
5×10
−4
×2×60
120×10
−3
=2
Now, A
1
v
1
=A
2
v
2
A
2
is
5
1
th of A
1
Hence v
2
is five times of v
1
or 10 m/s
t
0
=
g
2h
=
10
2×1
=0.447 s
R=v
2
t
0
=4.47 m
Answered by
1
Answer:
0.04 m
Step-by-step explanation:
Area of cross section = 8 cm^2
= 8/10000 m^2
Speed of water = 40kmph
= 40000/60 m per min
Time taken = 30 mins
Distance covered = Speed × Time
= 40000 × 30/60
= 20000 m
Volume of water flowed out = 8×20000/10000
= 16 m^3
Area of base of pool = 50×8 m^2
Depth of water = 16/50×8
=0.04 m
or
4 cm
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