Physics, asked by RakeshChowdary125, 6 months ago


The area of cross section of press is 5 m². Calculate force (in kgf) required to over come a resistive load of 500
kgf on it. The area of cross section of plunger is 0.02 m²:
(A) 5 kgf
(B) 2 kgf
(C) 10 kgf
(D) None of these

please help me​

Answers

Answered by catropnova
0

Explanation:

The area of cross section of press plunger

The area of cross-sections of the pump plunger and press plunger of a hydraulic press is 0.02 m2 and 8 m2 respectively. If the hydraulic press overcomes a load of 800 kgf, calculate the force Concept: Pressure - Pascal's Law.

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