Question

The area of cross section of press plunger of a hydraulic press is 4 m 2 . It is required to overcome a resistive load of 400 kgf on it. Calculate the force required on the pump plunger if the area of cross section of the pump plunger is 0.01m 2 .

Answer 1

Answer:

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Answer 2

Given:

Resistive Load (F1) = 400kgf

Area of the cross-section of press plunger (a1) = 4m²

Area of the cross section of pump plunger (a2) = 0.01m²

To Find:

The force is required on the pump plunger (F2).

Solution:

The pressure on both sides of the hydraulic press will be equal.

The pressure on the press plunger of hydraulic press ⇒ P = F/a

Pressure on press plunger (P1) = 400kgf÷4m² = 100Pa

As we know that, Pressure on press plunger = Pressure on pump plunger

So, Pressure on pump plunger (P2)= F2÷0.01m²

⇒ 100 = F2÷ 0.01m²

⇒  F2 = 100×0.01  = 1kgf

Hence, the force on the pump plunger is 1kgf.