Question

.The area of cross section of the first end of a U-shaped tube is 0.001m² and that of
the second end is 1m² respectively. On applying a force on the first end of the tube, a
force of 10000N was experienced at the second end. Calculate the force experienced
at the first end of the tube?

Answer 1

Answer:

the answer is 10N

Explanation:

Pressure remains same in all parts of U tube according to Pascal's law

therefore,

$\frac{Force }{ Area} = constant$

Force at the first end is F1 =?

Force at the second end is F2= 10000N

Area at the first end of the tube A1=

$0.001 {m}^{2}$

Area at the second end of the tube is A2=

$1 {m}^{2}$

$\frac{F1}{ A1} = \frac{F2}{A2}$

on putting the values we get,

$\frac{F1}{0.001} = \frac{10000}{1} \\ F1 = 10000 \times 0.001$

F1 = 10N