Question

The area of cross section of the two arms of a hydraulic press are 1 cm² and 10 cm² respectively (as shown). A force of 5 N is applied on the water in the thinner arm. The force should be applied on the water in thicker arm so that the water may remain in equilibrium is, [ ]
a) 60 N
b) 40 N
c) 50 N
d) 30 N


I want explanation

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Answer 1

Answer:

For the water to remain in equilibrium, the pressure at same height i.e.,A and B should be same according to Pascals law,

5N/1cm²= xN/ 10cm²

x=50N

Answer 2

Explanation:

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