The area of cross section of the wider tube is 800 cm and mass placed on it is 12 kg. Find the height difference in both the arms
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Answer:
15 cm
Step-by-step explanation:
Given The area of cross section of the wider tube is 800 cm and mass placed on it is 12 kg, to find the height difference in both the arms
Area of the wider tube = 800 cm^2
weight of boy = 12 kg
density of water row = 10^3 kg/m^3
h = height difference in both the arms
So Atmospheric pressure be Pa
Pa + h row g = Pa + mg / A
h row g = m g / A
h = m / row A where row is density of water = 1000 kg / m^3
h = 12 / 1000 x 800 x 10^-4
h = 15 cm
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