Question

The area of cross-section of the wider tube shown in figure is 800 cm^2. If a mass of 12 kg is placed on the
massless piston, the difference in heights h in the level of water in the two tubes is:

(1) 10 cm
(2) 6 cm
(3) 15 cm
(4) 2 cm​

Answer 1

Answer:

h= 15 cm

Explanation:

Area of wider tide = 800 cm²

weight of boy = 12 kg

Density of water row = 10^3 kg/m^3

h is the difference if both arms.

Let atmospheric pressure he Pa

Pa + h × rho × g = Pa + m×g /a

h = m/A × rho

h = 12/1000× 800× 10^-4

h = 15cm.

Answer 2

The area of cross-section of the wider tube shown in figure is 800 cm^2. If a mass of 12 kg is placed on the

massless piston, the difference in heights h in the level of water in the two tubes is:

(1) 10 cm

(2) 6 cm

(3) 15 cm is right ans

(4) 2 cm​

Explanation: