The area of curvature of a solid is equal to the area of curvature of a solid elliptical tube. The height and diameter of the funnel are both 12 cm then find the length of the radius.
Please solve..
Answers
Answer:
Step-by-step explanation:
Given:-
The area of curvature of a solid is equal to the area of curvature of a solid elliptical tube. The height and diameter of the funnel are both
12 cm
To find:-
find the length of the radius.
Solution:-
The area of Curvature of the solid galaxy
=>surface area of a sphere=4πr²
Curved surface area of a solid elliptical tube
=>Curved surface area of the Cylinder
=>2πRh sq.units
Here areas of two solids are equal
height=diameter=12 cm
=>h=2R=12cm
=>R=6cm
=>4πr²=2πRh
=>2r²=Rh
=>2r2=6×12
=>2r²=72
=>r²=72/2
=>r²=36
=>r=±6cm
r can not be negative
r=6cm
Answer:-
The length of the radius=6cm
Answer:
Answer:
\huge{\boxed{\rm{\red{Radius=6cm}}}}
Radius=6cm
Step-by-step explanation:
Given:-
The area of curvature of a solid is equal to the area of curvature of a solid elliptical tube. The height and diameter of the funnel are both
12 cm
To find:-
find the length of the radius.
Solution:-
The area of Curvature of the solid galaxy
=>surface area of a sphere=4πr²
Curved surface area of a solid elliptical tube
=>Curved surface area of the Cylinder
=>2πRh sq.units
Here areas of two solids are equal
height=diameter=12 cm
=>h=2R=12cm
=>R=6cm
=>4πr²=2πRh
=>2r²=Rh
=>2r2=6×12
=>2r²=72
=>r²=72/2
=>r²=36
=>r=±6cm
r can not be negative
r=6cm
Answer:-
The length of the radius=6cm