Question

The area of each plate of a parallel-plate capacitor is
100 cm and the distance between them is 0.05 cm.
When it is filled with a dielectric, its capacitance becomes
3.54 x 10- F. Find the dielectric constant. Ans. 2.0.
​

Answer 1

C=keoA/d

So

3.54×10^-6=k 8.85×10^-12×100×10^-2/0.05

You can easily Find k

Answer 2

Answer:2.0

Explanation:

Area=100cm^2=100cm*100cm=10^-2m*10^-2m=10^-4m^2

D=0.05cm=0.05*10^-2m

C=3.54*10^-10F

Now;

C=kEoA/D

K=CD/EoA

K=(3.54*10^-10)*(0.05*10^-2)/(8.85*10^-12)*(100*10^-4)

K=2.0(answer)