the area of equilateral triangle 49 root 3. taking each vertex as centre circle are described with radius is equal to half the length of the side of the triangle.find the area of the part of the triangle is not included in the circle (take root3=1.73 pie 22/7
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Area of equilateral triangle = ((✓3)/4)×s^2
where s is the length of side.
We know that area is 49✓3 so using that we find the side length.
Well find that s = 14.
so the radius r = (s/2) = 7
each angle of an equilateral triangle is 60 degrees. when you construct such a diagram as given in the question you will find that (1/6)th of each circle's area overlaps with that of the triangle.
now there are 3 circles so total overlapping area = 3(1/6) of area of circle.
which is half the area of the circle
Area overlapped =(πr^2)/2
Therefore Area not included
= 49✓3 - (π(7)^2)/2
=7.901 sq. units (approximately)
where s is the length of side.
We know that area is 49✓3 so using that we find the side length.
Well find that s = 14.
so the radius r = (s/2) = 7
each angle of an equilateral triangle is 60 degrees. when you construct such a diagram as given in the question you will find that (1/6)th of each circle's area overlaps with that of the triangle.
now there are 3 circles so total overlapping area = 3(1/6) of area of circle.
which is half the area of the circle
Area overlapped =(πr^2)/2
Therefore Area not included
= 49✓3 - (π(7)^2)/2
=7.901 sq. units (approximately)
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