The area of equilateral triangle is 49 root 3 three arc are drawn wuth the vertice of triangle as cebtre and radius is equal to half of side of triangle find thearea of triangle not included
in sector
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GIVEN:
Area of ∆ABC = 49√3
θ = 60° (angle of an equilateral ∆)
Let the each side of the ∆ be a cm.
Area of equilateral triangle = (√3/4) × side ²
49√3 = (√3/4) × a²
a² = 49√3 ×( 4 /√3) = 49 × 4
a= √49 × 4 = 7 × 2 = 14 cm
Radius of the circle half the length of the side of the ∆ABC (GIVEN)
Radius of the circle = ½ × 14 = 7 cm
Area of sector =(θ/360) × πr²
Area of sector = (60/360) × 22/7 × 7²
= ⅙ × 22 × 7= 154/6 = 77/3 cm²
Required area = Area of ∆ABC - 3 ( area of a sector of angle 60° in a circle of radius 7 cm)
Required area = 49√3 - 3×77/3
= 49√3 - 77
= 49 × 1.73 -77 = 84.77 - 77 = 7.77 cm²
Hence, the area of the triangle not included in the circle is 7.77 cm²
HOPE THIS WILL HELP
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