Math, asked by anshulsood6634, 1 year ago

The area of equilateral triangle is 49 root 3 three arc are drawn wuth the vertice of triangle as cebtre and radius is equal to half of side of triangle find thearea of triangle not included
in sector

Answers

Answered by adesh03umesh
0

GIVEN:

Area of ∆ABC = 49√3

θ = 60° (angle of an equilateral ∆)

Let the each side of the ∆ be a cm.

Area of equilateral triangle = (√3/4) × side ²

49√3 = (√3/4) × a²

a² = 49√3 ×( 4 /√3)  = 49 × 4

a= √49 × 4 = 7 × 2 = 14 cm

Radius of the circle half the length of the side of the ∆ABC (GIVEN)

Radius of the circle = ½ × 14 = 7 cm

Area of sector =(θ/360) × πr²

Area of sector = (60/360) × 22/7 × 7²

= ⅙ × 22 × 7= 154/6 = 77/3 cm²

Required area = Area of ∆ABC - 3 ( area of a sector of angle 60° in a circle of radius 7 cm)

Required area = 49√3 - 3×77/3

= 49√3 - 77

= 49 × 1.73 -77 = 84.77 - 77 = 7.77 cm²

Hence, the area of the  triangle not included in the circle is 7.77 cm²

HOPE THIS WILL HELP

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