Question

The area of four walls is 120 m² of a room. If length of the room is twice its breadth and height is 4m. Find the area of the floor.​

Answer 1

Answer:

Let breadth of the room = b m

Length= 2b m

Height= h= 4m

area of the four walls of the room = 2(length+breadth)*h

2(2b+b)*4=120m^2

8*3b=120

b=120/(8*3)

b=5m

Therefore

Breadth=b=5m

Length=2b=2*5=10m

2)area of the floor= length*breadth

=10m*5m

=50m^2

Step-by-step explanation:

please mark me as brainiest answer

Answer 2

$\begin{gathered}\begin{gathered}\bf \: Given - \begin{cases} &\sf{Area_{(four walls)} = 120 \: {m}^{2} } \\ &\sf{length = 2 \times breadth}\\ &\sf{height = 4 \: m} \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\bf \: To\:find - \begin{cases} &\sf{Area_{(floor)}}  \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\Large{\bold{{\underline{Formula \: Used \::}}}} \end{gathered}$

$(1). \: \boxed{ \tt \: Area_{(four \: walls)} = 2(length + breadth) \times height}$

$(2). \: \boxed{ \tt \: Area_{(floor)} = length \times breadth}$

$\large\underline{\bold{Solution :- }}$

• Let breadth of floor be 'x' meter.

So,

• Length of floor = 2x meter.

• Height of floor = 4 meter.

$\large \underline{\tt \:{ According \: to \: statement }}$

$\rm :\longmapsto\:Area_{(four walls)} = 120 \: {m}^{2}$

$\rm :\implies\:2(x + 2x) \times 4 = 120$

$\rm :\implies\:3x = 15$

$\rm :\implies\:x = 5$

Hence,

$\begin{gathered}\begin{gathered}\bf \: Dimensions \: of \: floor \: - \begin{cases} &\sf{breadth = x = 5 \: m} \\ &\sf{length = 2x = 10 \: m} \end{cases}\end{gathered}\end{gathered}$

Hence,

• Area of floor is given by,

$\rm :\longmapsto\:Area_{(floor)} = length \times breadth$

$\rm :\longmapsto\:Area_{(floor)} =5 \times 10$

$\rm :\longmapsto\: \boxed{ \bf{Area_{(floor)} = \: 50 \: {m}^{2} }}$

Additional Information

Cube: 

• A cube is a three-dimensional shape which is defined XYZ plane. It has six faces, eight vertices and twelve edges. All the faces of the cube are in square shape and have equal dimensions.

Cuboid: 

• A cuboid is also a polyhedron having six faces, eight vertices and twelve edges. The faces of the cuboid are parallel. But not all the faces of a cuboid are equal in dimensions.

Formula's of Cube :-

Total Surface Area = 6(side)²

Curved Surface Area = 4(side)²

Volume of Cube = (side)³

Diagonal of a cube = √3(side)

Perimeter of cube = 12 x side

Formula's of Cuboid

Total Surface area = 2 (Length x Breadth + breadth x height + Length x height)

Curved Surface area = 2 height(length + breadth)

Volume of the cuboid = (length × breadth × height)

lDiagonal of the cuboid =√(l² + b² + h²)

Perimeter of cuboid = 4 (length + breadth + height)