Question

the area of four walls of a cube if the length of the diagonal 6root 3 is​

Answer 1

heya mate...!!❤

Given :

The length of the diagonal of cube = 6√3

We know :

Diagonal of cube = √3 a

6√3 = √3 a

a = 6

Now :

Area of four walls of a cube = C.S.A of cube

C.S.A of cube = $4{a}^{2}$

$= 4 \times {6}^{2}$

$= 4 \times 36$

= 144

hope it helps..!!❤

Answer 2

$\huge{\underline{\mathbb{\red{Answer}}}}$

$\huge{\underline{\mathbb{\pink{Given}}}}$

The length of the diagonal of cube = 6√3

We know :

Diagonal of cube = √3 a

6√3 = √3 a

a = 6

$\huge{\underline{\mathbb{\red{NOW}}}}$

Area of four walls of a cube = C.S.A of cube

$c.s.a \: \: of \: \: cube = {4a}^{2}$

$= > 4 \times {6}^{2}$

$= > 4 \times 36$

= 144

$answer = 144$

$\huge{\red{\ddot{\smile}}}$

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$\huge{\underline{\underline{\mathfrak{Thank you}}}}$